Qoihak Erngiong(科學應用)

Sorhak    Diexnnao tengseg

Sorhak  (Yha ee debok si iuu Lamid zhehkiok sor zhud ee sioyhak 4 nii Sorhak qoirpurn.)

(1) Acie buea 1 paw koecie 155 qof, lexnggoa koiq buea cidkoafar diafmsym, hap~qylaai dwhoir si 370 qof. Chviar mng acie sor buea ee diafmsym si joa zue qof?(姊姊買了一包瓜子155元，另外又買了一些點心，合起來剛好是370元。請問姊姊所買的點心是多少元？)

    Dab: 370 qof - 155 qof = 215 qof

(2) Zuykiao 1 pvoaa u 15 liap, bue diau 7 pvoaa. Chviar mng zofngkiong bue diau joa zue liap zuykiao?(水餃1盤有15顆，賣了7盤。請問總共賣了多少顆水餃？)

    Dab: 15 liap x 7 (pvoaa) = 105 liap

Sviu qvoarmai ?(想想看)

    Kaxngqoarn ee debok naxsi iong TLPA laai siar karm exeng~did? Ie de (2) dee laikorng TLPA siar zoix(同樣的題目，如果用TLPA來寫的話，可以用嗎？以第(2)題來說，TLPA寫成):

(2) Cui2 kiau2 1 puann5 u7 15 liap8, bue7 diau7 7 puann5. Chiann2 mng7 cong2 kiong7 bue7   diau7 jua7 cue7 liap8 cui2 kiau2?

(2) Cui² kiau² 1 puann⁵ u⁷ 15 liap⁸, bue⁷ diau⁷ 7 puann⁵. Chiann² mng⁷ cong² kiong⁷ bue⁷   diau⁷ jua⁷ cue⁷ liap⁸ cui² kiau²?

Chviar mng larn ee sioir-pengiuo ee liaqkoong iar be?(請問我們的小朋友們會不會抓狂？)

Diexnnao tengseg

Chviar iong C gygieen siar zhud iuu zefngsox 1 kaf kaux n ee hamsox.(以C語言寫出從1加到n的函數)

// Di citee tengseg laixbin, bexngleng kaxngqoarn poychii iong Engbuun-seg ee.

// Daxnsi piernsox iong Daibuun laai dexnggi. Qvoax~qylaai cyn zuxjieen.

int Kahoad(int n)

{

  int Zofngsox = 0;

  for(int i=1; i<n; i++) Zofngsox = Zofngsox + i;

  return Zofngsox;

}

// Exbin citee tengseg si qngx di Zngf Serngioong kaosiu ee zheq: "Zusixn-hoa Phofsit Daibuun".

// Mxkoarn si bexngleng iafsi piernsox, zoanpo lorng iong Daibuun laai qaihoad.

// Qvoax~qylaai maxsi cyn zuxjieen. (Laixbin goar u zoix sioir-sioir ee siukae)

/* Duix d*n sioyii b seng 2 ee n zhuohofng. */

/* Zhue zhud siang sioir ee n. */

#dexnggi DY 10000.0  // Dy ee keacvii si 10000 qof.

#dexnggi BIE 0.01      // Bie ee keacvii si 0.01 qof.

#dexnggi DEA 2      // Zhuohofng ee defsox si 2

zwtengseg()

{

  zerng Kafng;   // Kafng si cidee zefngsox

  phuu  Lie_ee_cvii, Goar_ee_cvii;  // Lie_ee_cvii kab Goar_ee_cvii lofngsi phudiarm-sox.

  Lie_ee_cvii = 1;

  Goar_ee_cvii = 1;

  Kafng = 1;    // Sietdeng qyzhof cid

  dngf(Lie_ee_cvii > Goar_ee_cvii)

  {

    Lie_ee_cvii = DY * Kafng;

    Goar_ee_cvii = BIE * zhuohofng(DEA, Kafng);

    Kafng ++;

  }  // dngf ee kietsog

  irnzhud(" Kengkuex %5z kafng\n", Kafng);

  irnzhud(" Lie ee cvii si %9.3p qof\n", Lie_ee_cvii);

  irnzhud(" Goar ee cvii si %9.3p qof\n", Goar_ee_cvii);

}  // tengseg kietsog

Sviu qvoarmai ?(想想看)

    Kitvaf ee phengym hextorng, chviu POJ(Kaolooi) iafsi TLPA,  zoix ue kaux citee kerngkaix boq? (其他的拼音系統，如白話字(教羅)或TLPA，做得到這種境界嗎？)

Derng cit iah    Siang defngbin